To find the probability of at least 1 baby being born early, we need to find the probability of none of the babies being born early and subtract it from 1. The probability of a baby not being born early is 80%, or 0, 2, 3, 4, 5, 6, 7, 8, or 9 on the table. So, the probability of none of the 5 babies being born early is:
0.8 x 0.8 x 0.8 x 0.8 x 0.8 = 0.32768
Therefore, the probability of at least 1 baby being born early is:
1 - 0.32768 = 0.67232 or 67.232% (rounded to the nearest thousandth)
Suppose 20% of babies born are born early, 50% are born on time, and 30% are born late. A nurse uses a random-number table to find the experimental probability that of 5 births, at least 1 baby will be born early. The digits 0 and I represent babies born early. The digits 2, 3, 4, 5, and 6 represent babies born on time. The digits 7, 8, and 9 represent babies born late.
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