Suppose 100.0 mL of 1.00 M HCl and 100.0 mL of 1.00 M NaOH, both initially at 23.0°C, are mixed in a thermos flask. When the reaction is complete, the temperature is 29.8°C. Assuming that the solutions have the same heat capacity as pure water, compute the heat released (in kJ).

Answer 1

........HCl + NaOH ==> NaCl + H2O

mols HCl = 0.1 x 1.00 = 0.1
mols NaOH = 0.1 x 1.00 = 0.1
mols H2O produced = 0.1
q = mass x specific heat H2O x (Tfinal-Tinitial)
q = 200 x 4.184 x (29.8-23.0)
That gives q for 0.1 mol in J. Convert to kJ/mol if desired.