Suppose 1.5 g of Compound A are consumed in a reaction with 9.0 g of Compound B that produces only one product, Compound C.

Question

Calculate the theoretical yield of C
Round your answer to nearest .1 g

Answer 1

To calculate the theoretical yield of Compound C, we'll follow these steps:

1. Determine the molar masses of Compounds A, B, and C.
2. Determine the limiting reagent.
3. Use stoichiometry to find the amount of Compound C that can be formed.
4. Convert moles of Compound C to grams.

For this example, we'll assume we are given the molar masses of the compounds or can look them up. However, since no chemical equation or molecular weights are provided, I'll illustrate the process assuming hypothetical molar masses.

Let's assume:
- Molar mass of Compound A (M_A) = 50 g/mol
- Molar mass of Compound B (M_B) = 30 g/mol
- Molar mass of Compound C (M_C) = 70 g/mol
- The balanced chemical equation is: \( A + 2B \rightarrow C \)

### Step 1: Convert grams to moles
Convert the masses of Compounds A and B to moles using their respective molar masses.

\[
\text{Moles of A} = \frac{1.5 \text{ g}}{50 \text{ g/mol}} = 0.03 \text{ mol}
\]

\[
\text{Moles of B} = \frac{9.0 \text{ g}}{30 \text{ g/mol}} = 0.3 \text{ mol}
\]

### Step 2: Determine the limiting reagent
The reaction consumes 1 mole of A for every 2 moles of B. Therefore:

The ratio of moles required is:
\[ \text{Moles of B required for 0.03 mol A} = 0.03 \text{ mol A} \times 2 = 0.06 \text{ mol B} \]

We have 0.3 moles of B available, which is more than enough to react with 0.03 moles of A. Hence, Compound A is the limiting reagent.

### Step 3: Calculate the moles of Compound C produced
From the balanced equation, 1 mole of A produces 1 mole of C. Therefore:

\[
\text{Moles of C} = \text{Moles of A} = 0.03 \text{ mol}
\]

### Step 4: Convert moles of Compound C to grams
\[
\text{Mass of C} = \text{Moles of C} \times \text{Molar mass of C}
\]
\[
\text{Mass of C} = 0.03 \text{ mol} \times 70 \text{ g/mol} = 2.1 \text{ g}
\]

### Conclusion
The theoretical yield of Compound C is 2.1 grams.

Note: Replace the hypothetical molar masses and reaction equation with the actual values if they are given to get the specific result for your problem.