Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Suppose 0.0150 kg of steam (at 100.00°C) is added to 0.150 kg of water (initially at 19.3°C.). The water is inside a copper cup...Asked by help me please
Suppose 0.0150 kg of steam (at 100.00°C) is added to 0.150 kg of water (initially at 19.3°C.). The water is inside a copper cup of mass 54.1 g. The cup is inside a perfectly insulated calorimetry container that prevents heat flow with the outside environment. Find the final temperature (in °C) of the water after equilibrium is reached.
Answers
Answered by
bobpursley
The sum of the heats gained is zero.
Heatcodensingsteam+heatcondensedsteamTofinalTemp+heatwater to finaltemp+heatcopper to finaltemp=0
Heat gained condensing steam=-.00150*Hv the sign is negative because heat is LOST.
Heat gained by condensed steam=.0150(cw)(Tf-100)
Heat gained by heated water=.150*Cw*(Tf-19.3)
Heat gained by copper=.054(Ccu)(Tf-19.3)
add all these, set to zero, and solve for Tf.
Heatcodensingsteam+heatcondensedsteamTofinalTemp+heatwater to finaltemp+heatcopper to finaltemp=0
Heat gained condensing steam=-.00150*Hv the sign is negative because heat is LOST.
Heat gained by condensed steam=.0150(cw)(Tf-100)
Heat gained by heated water=.150*Cw*(Tf-19.3)
Heat gained by copper=.054(Ccu)(Tf-19.3)
add all these, set to zero, and solve for Tf.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.