Suppose 0.015 kg of steam (at 100.00 °C) is added to 0.20 kg of water (initially at 14.0°C). The water is inside an aluminum cup of mass 40 g. The cup is inside a perfectly insulated calorimetry container that prevents heat exchange with the outside environment. Find the final temperature of the water after equilibrium is reached.

Question

I'm not exactly sure on how to start this

Answer 1

The sum of the heats gained is zero (some are negative)
Heat gained by water+heat lost by steam condensing + heat gained by steamcondensate=0

masswater*c(Tf-ti)+masssteam*Hv+Masssteam*cwater*(Tf-100)=0

solve for Tf

Answer 2

oops, I fogot the aluminum contaniner , add in the heat gained by the aluminum container .040*Caluminum*(tf-Ti)