Supply the number so that the quadratic equation below has 6 and 8 as its solutions.

1 answer

To form a quadratic equation based on its roots (solutions), you can use the fact that if \( r_1 \) and \( r_2 \) are the roots of the equation, the quadratic can be expressed in the form:

\[ (x - r_1)(x - r_2) = 0 \]

Given roots \( r_1 = 6 \) and \( r_2 = 8 \), the equation can be constructed as follows:

  1. Substitute the values of \( r_1 \) and \( r_2 \):

\[ (x - 6)(x - 8) = 0 \]

  1. Expand the expression:

\[ x^2 - 8x - 6x + 48 = 0 \] \[ x^2 - 14x + 48 = 0 \]

Thus, the quadratic equation is:

\[ x^2 - 14x + 48 = 0 \]

In conclusion, the quadratic equation that has 6 and 8 as solutions is:

\[ x^2 - 14x + 48 = 0 \]