Sure! To check your understanding of the sums and products of rational numbers, here are some quick questions along with their solutions:
Quick Check Questions
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Sum of Rational Numbers: What is the sum of \( \frac{3}{4} \) and \( \frac{2}{3} \)?
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Product of Rational Numbers: What is the product of \( \frac{5}{6} \) and \( \frac{4}{9} \)?
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Sum with Mixed Numbers: What is the sum of \( 2 \frac{1}{2} \) and \( 1 \frac{3}{4} \)?
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Product of a Rational Number and an Integer: What is the product of \( \frac{7}{8} \) and \( 3 \)?
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Sum of Negative Rational Numbers: What is the sum of \( -\frac{2}{5} \) and \( -\frac{1}{3} \)?
Solutions
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Sum of \( \frac{3}{4} \) and \( \frac{2}{3} \): \[ \frac{3}{4} + \frac{2}{3} = \frac{3 \cdot 3}{4 \cdot 3} + \frac{2 \cdot 4}{3 \cdot 4} = \frac{9}{12} + \frac{8}{12} = \frac{17}{12} \]
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Product of \( \frac{5}{6} \) and \( \frac{4}{9} \): \[ \frac{5}{6} \times \frac{4}{9} = \frac{5 \cdot 4}{6 \cdot 9} = \frac{20}{54} = \frac{10}{27} \quad (\text{after simplification}) \]
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Sum of \( 2 \frac{1}{2} \) and \( 1 \frac{3}{4} \): \[ 2 \frac{1}{2} = \frac{5}{2}, \quad 1 \frac{3}{4} = \frac{7}{4} \] \[ \frac{5}{2} + \frac{7}{4} = \frac{5 \cdot 2}{2 \cdot 2} + \frac{7 \cdot 1}{4 \cdot 1} = \frac{10}{4} + \frac{7}{4} = \frac{17}{4} \]
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Product of \( \frac{7}{8} \) and \( 3 \): \[ \frac{7}{8} \times 3 = \frac{7 \cdot 3}{8} = \frac{21}{8} \]
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Sum of \( -\frac{2}{5} \) and \( -\frac{1}{3} \): \[ -\frac{2}{5} + -\frac{1}{3} = -\left(\frac{2}{5} + \frac{1}{3}\right) = -\left(\frac{2 \cdot 3}{5 \cdot 3} + \frac{1 \cdot 5}{3 \cdot 5}\right) = -\left(\frac{6}{15} + \frac{5}{15}\right) = -\frac{11}{15} \]
Feel free to ask more questions if you'd like further practice or explanation!