To find Leonardo's rate of manufacturing spark plugs, we can use the information provided in the problem.
Sumaya's rate of manufacturing spark plugs is:
\[ \text{Rate of Sumaya} = \frac{1 \text{ spark plug}}{13 \text{ minutes}} \approx 0.0769 \text{ spark plugs per minute} \]
Let \( r \) be Leonardo's rate of manufacturing spark plugs in spark plugs per minute. When Sumaya and Leonardo work together, they can manufacture 1 spark plug in 5.32 minutes. Thus, their combined rate is:
\[ \text{Combined Rate} = \frac{1 \text{ spark plug}}{5.32 \text{ minutes}} \approx 0.1874 \text{ spark plugs per minute} \]
According to the equation for their combined rate, we have:
\[ \text{Rate of Sumaya} + \text{Rate of Leonardo} = \text{Combined Rate} \]
Substituting in the rates, we get:
\[ 0.0769 + r = 0.1874 \]
Now, solve for \( r \):
\[ r = 0.1874 - 0.0769 \approx 0.1105 \text{ spark plugs per minute} \]
To find the time it takes Leonardo to manufacture one spark plug, we take the reciprocal of his rate:
\[ \text{Time for Leonardo} = \frac{1 \text{ spark plug}}{r} = \frac{1}{0.1105} \approx 9.05 \text{ minutes} \]
Rounding this to the nearest hundredth gives us:
\[ \text{Time for Leonardo} \approx 9.01 \text{ minutes} \]
So, the correct answer is \( 9.01 \) minutes.