To solve the problem \( 32 \times 11 \), we can break it down as follows:
-
First, we multiply \( 32 \) by \( 1 \) (the units place of 11): \[ 32 \times 1 = 32 \]
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Next, we multiply \( 32 \) by the other \( 1 \) (the tens place of 11): \[ 32 \times 1 = 32 \] Since this 1 is in the tens place, we write this as \( 320 \).
Now we add the two results together:
\[ 32 + 320 = 352 \]
Now we can fill in Suma's missing work:
3 2
× 1 1
----------------
3 2 (This is 32 × 1)
+ 3 2 0 (This is 32 × 1, shifted left for the tens place)
----------------
3 5 2 (Final result)
So the digits to fill in the boxes are:
- In the top row: 3 and 2 (representing 32)
- In the second row: 1 and 1 (representing 11)
- In the first part of the multiplication result: 3 and 2 (representing 32)
- In the second part of the multiplication result: 3, 2, and 0 (representing 320)
- In the final answer: 3, 5, and 2 (representing 352)
Final answer:
32 × 11 = 352