Sum the following term of progression to the last term, logx, logx^2 logx^3.... logx^120

Answer 1

log x^n = n log x

so you have log x (1+2+3+4 ...120)

so log x times arithmetic sequence sum with a = 1, d = 1 n from 1 to 120
see
http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html