Sulphuric acid (H2SO4) solution reacts with magnesium metal (Mg) to

magnesium sulphate and hydrogen according to:
H2SO4 + Mg → MgSO4 + H2
How many litres of 5.00 M sulphuric acid would be required to dissolve
20.00 g of magnesium and how many mol of hydrogen would be
produced?
(RMM data: H = 1.01, S = 32.07, O = 16.00, Mg = 24.31)

2 answers

mols Mg = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Mg to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4. You know mols and M, solve for L.

Using mols Mg, convert to mols H2 for part 2.
m,mm