Sulfur trioxide dissolves in water, producing H2SO4. How much sulfuric acid can be produced from 12.1 mL of water (d=1.00g/mL) and 22.1 g of SO3?

2 answers

This is a limiting reagent problem which means that one of the reagents will be used completely and some of the other one will remain unreacted. You must figure which which is which.
Write the equation.
H2O + SO3 ==> H2SO4
2a. Convert g H2O to moles. moles = grams/molar mass.
2b. Convert g SO3 to moles.

3a. Convert moles H2O to moles H2SO4. These are all 1:1 relations so that should be easy to do.
3b. Convert moles SO3 to moles H2SO4.
3c. The correct one to choose for the limiting reagent is ALWAYS the smaller one.

4. Take the number from 3c and convert to grams. grams = moles x molar mass.

Post your work if you get stuck.
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