Sulfur dioxide a gas that plays a central role in the formation of acid rain, is found in the exhaust of automobile and power plant. Consider a 3.53 sample of gaseous Sulfur dioxide as a pressure of 7.6x10 pa. If the pressure is changed to 2.5x10pa at the constant temperature. What will be the new volume of the gas

Answer 1

To find the new volume of the gas, we can use the combined gas law equation:

(P1)(V1) / T1 = (P2)(V2) / T2

Where:
P1 = initial pressure = 7.6 x 10 Pa
V1 = initial volume (unknown)
T1 = initial temperature (constant)
P2 = final pressure = 2.5 x 10 Pa
V2 = final volume (unknown)
T2 = final temperature (constant)

Since the temperature is constant, T1 = T2, so we can cancel out the temperatures in the equation:

(P1)(V1) = (P2)(V2)

Now we can plug in the values and solve for V2:

(7.6 x 10)(V1) = (2.5 x 10)(3.53)
7.6V1 = 8.825

V1 = 8.825 / 7.6
V1 ≈ 1.163

Therefore, the new volume of the gas will be approximately 1.163 cubic meters.