1. Convert 0.179 g sulfamic acid to moles. moles = grams/molar mass.
2. Using the coefficients in the balanced equation, convert moles sulfamic acid to moles KOH.
3. Now use the definition of molarity = moles/L
sulfamic acid, HSO3NH2, is a strong monoprotic acid that can be used to standardize a strong base :
HSO3NH2(aq)+ KOH(aq) --> KSO3NH2(aq) + H20(l)
A .179g sample of HSO3NH2 required 19.4 mL of an aq soln of KOH for complete reaction. whats the molarity of KOH soln?
2 answers
This doesn't help