Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point) Responses Book A will require less wrapping paper because its surface area is 32.75 in.2 less than the surface area of Book B. Book A will require less wrapping paper because its surface area is 32.75 in.2 less than the surface area of Book B. Book B will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book A. Book B will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book A. Book B will require less wrapping paper because its surface area is 0.5 in.2 less than the surface area of Book A. Book B will require less wrapping paper because its surface area is 0.5 in.2 less than the surface area of Book A. Book A will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book B.

1 answer

To determine which book requires less wrapping paper, we need to calculate the surface area of each book.

The formula for the surface area S of a rectangular prism (box) is: S=2(lw+lh+wh)

Where:

  • l = length
  • w = width
  • h = height

Book A:

  • Length = 6.5 inches
  • Width = 1 inch
  • Height = 8.5 inches

Calculating the surface area: SA=2(6.51+6.58.5+18.5) =2(6.5+55.25+8.5) =2(70.25) =140.5 in2

Book B:

  • Length = 5.5 inches
  • Width = 2 inches
  • Height = 8 inches

Calculating the surface area: SB=2(5.52+5.58+28) =2(11+44+16) =2(71) =142 in2

Comparing Surface Areas:

  • Surface Area of Book A = 140.5 in²
  • Surface Area of Book B = 142 in²

Conclusion:

Book A has a surface area of 140.5 in², while Book B has a surface area of 142 in². Therefore, Book A will require less wrapping paper because its surface area is 1.5 in.² less than the surface area of Book B.