Sue is wrapping books to give as gifts book a has a length of 6.5 in and width of 1 in and has a height of 8.5 in book b has a length of 5.5 in a width of 2 in and a height of 8 in based on the surface area which book will require less wrapping paper

Answer 1

To calculate the surface area of each book, we will find the area of each side and then add them up.

For book A:
- The area of the front and back sides is equal to the length multiplied by the height: 6.5 in * 8.5 in = 55.25 square inches
- The area of the two smaller sides is equal to the width multiplied by the height: 2 * (1 in * 8.5 in) = 17 square inches
- The area of the top and bottom sides is equal to the length multiplied by the width: 6.5 in * 1 in = 6.5 square inches

Adding up all the areas, the surface area of book A is: 55.25 sq in + 17 sq in + 6.5 sq in = 78.75 square inches

For book B:
- The area of the front and back sides is equal to the length multiplied by the height: 5.5 in * 8 in = 44 square inches
- The area of the two smaller sides is equal to the width multiplied by the height: 2 * (2 in * 8 in) = 32 square inches
- The area of the top and bottom sides is equal to the length multiplied by the width: 5.5 in * 2 in = 11 square inches

Adding up all the areas, the surface area of book B is: 44 sq in + 32 sq in + 11 sq in = 87 square inches

Therefore, book A will require less wrapping paper as it has a smaller surface area than book B.