To solve the problem, we can set up a system of equations based on the information provided.
Let \( n \) be the number of nickels and \( q \) be the number of quarters. We have the following information:
- The total number of coins is 16.
- The total value of the coins is $2, which is equivalent to 200 cents.
From this information, we can formulate our equations:
- \( n + q = 16 \) (Equation 1: total number of coins)
- \( 5n + 25q = 200 \) (Equation 2: total value of the coins in cents)
Now, we can simplify Equation 2 by dividing all terms by 5:
\[ n + 5q = 40 \] (Equation 3)
Now, we can solve the system of equations using Equation 1 and Equation 3.
Step 1: From Equation 1, express \( n \) in terms of \( q \):
\[ n = 16 - q \]
Step 2: Substitute \( n \) into Equation 3:
\[ (16 - q) + 5q = 40 \]
Step 3: Combine like terms:
\[ 16 + 4q = 40 \]
Step 4: Solve for \( q \):
\[ 4q = 40 - 16 \] \[ 4q = 24 \] \[ q = 6 \]
Step 5: Substitute back to find \( n \):
\[ n = 16 - q \] \[ n = 16 - 6 \] \[ n = 10 \]
Conclusion:
Sue received 10 nickels and 6 quarters.
To summarize the values:
| | quantity | value each | total value | |----------|----------|------------|-------------| | Nickels | 10 | 5 | 50 | | Quarters | 6 | 25 | 150 | | Together | 16 | | 200 |
Thus, the solution confirms that Sue has 10 nickels and 6 quarters for a total value of $2.