Prob(m) = 1/5
prob(S) = 4/5
Possible outcomes in best of three"
MM --- (1/5)(1/5) = 1/25
MSM -- ((1/5)(4/5)(1/5) = 4/125
SMM -- ((4/5)(1/5)(1/5) = 4/125
SS ---- (4/5)(4/5) = 16/25 ----> Sue wins
SMS -- (4/5)(1/5)(4/5) = 16/125 ----> Sue wins
MSS -- ((1/5)(4/5)(4/5) = 16/125---> Sue wins
prob(sue wins) = 16/25+16/125+16/125 = 112/125 or .896
add them up to get 1 as a check
you said "I have that the chance of winning best of three is 0.50"
How so ??
Sue and Mary agree to play the best of three games of badminton. They stop if either of them have won two games. Over a long period of time, Sue wins 4 games out of every 5 games they play. Find the probability that Sue will win the best of three.
I have that the chance of winning best of three is 0.50 but not sure what next.?
1 answer
3 answers