Let's break this problem down into simpler steps.
Step 1: Find the slope (m) of the line using the two points (-3, 4) and (6, 10).
m = (10 - 4) / (6 - (-3))
m = 6 / 9
m = 2/3
Step 2: Use the slope-intercept form of the equation of a line (y = mx + b) to find the y-intercept (b).
y = mx + b
4 = (2/3)(-3) + b
4 = -2 + b
b = 6
Step 3: Write the equation of the line using the slope-intercept form.
y = 2/3x + 6
Now, let's write a recursive function to represent this same relationship:
Function: find_y
Inputs: x (the x-coordinate of a point on the line)
Output: y (the corresponding y-coordinate of the point on the line)
If x equals -3:
y = 4
Else:
y = 2/3 * x + 6
Return y
This recursive function calculates the y-coordinate of a point on the line by plugging the x-coordinate into the equation y = 2/3x + 6.
Sue and Kathy were doing their algebra homework. They were asked to write the equation of the line that passed through the points (-3, 4) and (6, 10). Sue wrote
y - 4 2/3(x + 3) and Kathy wrote y = 2/3x + 6. Write a recursive function to represent this same relationshipwirtten as a 8th grader
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