Suddenly losing his thirst, Mathman decides to check out the festivities, but just then, Frankenstein ran by him screaming, "Cheater, cheater, apple eater." It seems that Dracula had illegally been using his bicuspids to win at apple-bobbing. Frankenstein was furious and ran outside with the apple. He then heaved it skyward at a rate of 192 feet per second. If he released the apple at a height of 10 feet, how high did the apple go? When did it return to the ground?

Question

Thanks

Answer 1

h = 10 + 192t - 16t^2

This reaches its peak at t = -192/-32 = 6

h(6) = 586 feet
h = 0 when t = 12.05 sec