Sucrose (C₁₂H₂₂O₁₁) is combusted in air according to the following reaction:

Question

C₁₂H₂₂O₁₁(s) + O₂(g) → CO₂(g) + H₂O(l)
How many moles of carbon dioxide would be produced by the complete combustion of 66.8 grams of sucrose in the presence of excess oxygen?

Answer 1

how many moles of sucrose in 66.8 g?
C₁₂H₂₂O₁₁(s) + 12O₂(g) → 12CO₂(g) + 11H₂O(l)
each mole of sucrose produces 12 moles of CO2

Answer 2

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