To subtract the mixed numbers \( 9 \frac{2}{3} \) and \( 6 \frac{1}{3} \), first, we convert them into improper fractions.
-
Convert \( 9 \frac{2}{3} \): \[ 9 \frac{2}{3} = 9 \times 3 + 2 = 27 + 2 = \frac{29}{3} \]
-
Convert \( 6 \frac{1}{3} \): \[ 6 \frac{1}{3} = 6 \times 3 + 1 = 18 + 1 = \frac{19}{3} \]
Now, we can perform the subtraction: \[ 9 \frac{2}{3} - 6 \frac{1}{3} = \frac{29}{3} - \frac{19}{3} \]
Since the fractions have a common denominator, we can subtract the numerators: \[ \frac{29 - 19}{3} = \frac{10}{3} \]
Next, we can convert \( \frac{10}{3} \) back to a mixed number:
- Divide 10 by 3, which gives us 3 with a remainder of 1. Thus: \[ \frac{10}{3} = 3 \frac{1}{3} \]
Therefore, the answer is: \[ \boxed{3 \frac{1}{3}} \]
1 answer