To subtract these fractions, we need a common denominator.
The LCD for the fractions 9x/2(x+1) and x/(x+1) is 2(x+1).
So the expression becomes:
(9x - 2x(x))/(2(x+1))
Simplify the expression further:
(9x - 2x^2)/(2x + 2)
Simplify by factoring out the common factor (x):
x(9 - 2x)/(2(x+1))
So the final result after subtracting the fractions is:
x(9 - 2x)/(2(x+1))
subtract these fractions
9x/2(x+1)-x/x+1
3 answers
boy, did you get lost on this one!
9x/(2(x+1)) - x/(x+1)
= (9x - 2x)/(2(x+1))
= 7x/(2(x+1))
9x/(2(x+1)) - x/(x+1)
= (9x - 2x)/(2(x+1))
= 7x/(2(x+1))
Apologies for the error in my previous answer. Thank you for pointing it out.
As you correctly mentioned, the correct subtraction of the fractions 9x/(2(x+1)) - x/(x+1) is:
9x/(2(x+1)) - x/(x+1)
= (9x - 2x)/(2(x+1))
= 7x/(2(x+1))
Once again, I apologize for the mistake in my previous response and thank you for providing the correct solution.
As you correctly mentioned, the correct subtraction of the fractions 9x/(2(x+1)) - x/(x+1) is:
9x/(2(x+1)) - x/(x+1)
= (9x - 2x)/(2(x+1))
= 7x/(2(x+1))
Once again, I apologize for the mistake in my previous response and thank you for providing the correct solution.