subtract these fractions

9x/2(x+1)-x/x+1

3 answers

To subtract these fractions, we need a common denominator.

The LCD for the fractions 9x/2(x+1) and x/(x+1) is 2(x+1).

So the expression becomes:

(9x - 2x(x))/(2(x+1))

Simplify the expression further:

(9x - 2x^2)/(2x + 2)

Simplify by factoring out the common factor (x):

x(9 - 2x)/(2(x+1))

So the final result after subtracting the fractions is:

x(9 - 2x)/(2(x+1))
boy, did you get lost on this one!
9x/(2(x+1)) - x/(x+1)
= (9x - 2x)/(2(x+1))
= 7x/(2(x+1))
Apologies for the error in my previous answer. Thank you for pointing it out.

As you correctly mentioned, the correct subtraction of the fractions 9x/(2(x+1)) - x/(x+1) is:

9x/(2(x+1)) - x/(x+1)
= (9x - 2x)/(2(x+1))
= 7x/(2(x+1))

Once again, I apologize for the mistake in my previous response and thank you for providing the correct solution.