To subtract the rational expressions \(\frac{x^2 - 2}{4x - 7}\) and \(\frac{x + 4}{4x - 7}\), we can combine them since they have the same denominator.
The expression is as follows:
\[ \frac{x^2 - 2}{4x - 7} - \frac{x + 4}{4x - 7} \]
Since the denominators are the same, we can write:
\[ \frac{(x^2 - 2) - (x + 4)}{4x - 7} \]
Now, let's simplify the numerator:
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Distribute the negative sign: \[ (x^2 - 2) - (x + 4) = x^2 - 2 - x - 4 \]
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Combine like terms: \[ x^2 - x - 2 - 4 = x^2 - x - 6 \]
Now, we substitute back into our expression:
\[ \frac{x^2 - x - 6}{4x - 7} \]
Next, we can try to factor the numerator \(x^2 - x - 6\):
To factor \(x^2 - x - 6\), we need two numbers that multiply to \(-6\) and add up to \(-1\). Those numbers are \(-3\) and \(2\). So we can write:
\[ x^2 - x - 6 = (x - 3)(x + 2) \]
Substituting this back into the expression, we get:
\[ \frac{(x - 3)(x + 2)}{4x - 7} \]
Therefore, the final answer for the difference is:
\[ \frac{(x - 3)(x + 2)}{4x - 7} \]