Subtract the polynomial 4x^2-3x+5 from 6x^2+x-2

1 answer

To subtract the polynomial \(4x^2 - 3x + 5\) from \(6x^2 + x - 2\), we can express this operation as:

\[ (6x^2 + x - 2) - (4x^2 - 3x + 5) \]

Now, distribute the negative sign across the second polynomial:

\[ 6x^2 + x - 2 - 4x^2 + 3x - 5 \]

Next, combine like terms:

  1. For the \(x^2\) terms: \(6x^2 - 4x^2 = 2x^2\)
  2. For the \(x\) terms: \(x + 3x = 4x\)
  3. For the constant terms: \(-2 - 5 = -7\)

Putting it all together, we have:

\[ 2x^2 + 4x - 7 \]

So, the result of the subtraction is:

\[ \boxed{2x^2 + 4x - 7} \]

Similar Questions
    1. answers icon 0 answers
    1. answers icon 1 answer
  1. 1.add or subtract.(4x²+15x-3)-(-3x²+5) A:7x²+15x-8*** B:x²+12x+2 C:x²+15x-8 D:7x²+8 2.Simplify the polynomial.
    1. answers icon 7 answers
  2. 1.add or subtract.(4x²+15x-3)-(-3x²+5) A:7x²+15x-8 B:x²+12x+2 C:x²+15x-8 D:7x²+8 2.Simplify the polynomial.
    1. answers icon 1 answer
more similar questions