To subtract the terms \(\sqrt{50x}\) and \(\sqrt{18x}\), we first simplify each radical.
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Simplifying \(\sqrt{50x}\): \[ \sqrt{50x} = \sqrt{25 \cdot 2 \cdot x} = \sqrt{25} \cdot \sqrt{2} \cdot \sqrt{x} = 5\sqrt{2x} \]
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Simplifying \(\sqrt{18x}\): \[ \sqrt{18x} = \sqrt{9 \cdot 2 \cdot x} = \sqrt{9} \cdot \sqrt{2} \cdot \sqrt{x} = 3\sqrt{2x} \]
Now we subtract the two simplified terms: \[ \sqrt{50x} - \sqrt{18x} = 5\sqrt{2x} - 3\sqrt{2x} \] This can be combined since they are like terms: \[ (5 - 3)\sqrt{2x} = 2\sqrt{2x} \]
Therefore, the answer is: \[ \boxed{2\sqrt{2x}} \]
So, the correct choice is:
A. \( 2\sqrt{2x} \) (Please type an exact answer using radicals as needed.)