To subtract [c-3d-e] from the sum of [4c+d-e] and [2c-3d+2e], first simplify the sum:
[4c+d-e] + [2c-3d+2e] = 6c - 2d + e
Then, subtract [c-3d-e]:
(6c - 2d + e) - (c - 3d - e) = 6c - 2d + e - c + 3d + e
Simplifying further:
6c - c - 2d + 3d + e + e = 5c + d + 2e
Therefore, the answer is 5c + d + 2e.
subtract [c-3d-e]from the sum of [4c+d-e] and [2c-3d+2e]
1 answer