Subtract and Simplify:

Question

4a^2/(a-b)-(4b^2-8ab)/(b-a)
I have the answer as 4(a+b)^2/(a-b)

or should it be 4(a-b)^2/(a-b)

Responses

Math problem check - bobpursley, Sunday, October 12, 2008 at 4:23pm

just the numerator..

4a^2-8ab + 4b^2, right?
4(a-b)^2

Now does that reduce with the denominator?



Math problem check - Shawn, Sunday, October 12, 2008 at 4:28pm
Okay I have the answer as 4(a-b) is that right

Math problem check - Shawn, Sunday, October 12, 2008 at 4:37pm
What about
4a^2/(a-b)-(4b^2-8ab)/(b-a)
I thought that you would multiple the second part of the equation by -1
-(4b^2-8ab)/(b-a)
to get the common LCD of a-b
So I thought the equation would be 4a^2/(a-b) + (4b^2 + 8ab)/(a-b)

I have the answer as 4(a+b)^2/(a-b)

Answer 1

You are wrong.

THe second part only..

-4(b^2-2ab)/(b-a)
+4(b^2-2ab)/(a-b)

Your answer is still wrong.