Question

Subtract (3b-2c) -(6c+2b) -(b+c)

Answer 1

To subtract these expressions, we need to distribute the negative sign to each term in the second and third expressions:

(3b - 2c) - (6c + 2b) - (b + c)

= 3b - 2c - 6c - 2b - b - c

Now, we can combine the like terms:

= (3b - 2b - b) - (2c - 6c - c)

= 0b - 8c

= -8c

Therefore, the final answer is -8c.