Subtract: (3b-2c)-(6c+2b)-(b+c)

Answer 1

To solve this expression:

(3b - 2c) - (6c + 2b) - (b + c)

We can start by distributing the negative sign to the terms inside the parentheses:

3b - 2c - 6c - 2b - b - c

Next, we can combine like terms by combining the coefficients of the variables:

(3b - 2b) - (2c + 6c + c) - b - c

This simplifies to:

b - 9c - b - c

Finally, we can combine the remaining like terms:

(b - b) - (9c + c)

The variables with coefficients of 1 and -1 cancel each other out, leaving:

0 - 10c

The final result is:

-10c