Subtract (3b-2c)- (6c+2b)-(b+c)

Answer 1

To subtract the given expressions, we need to distribute the negative signs for the second and third sets of parentheses and then combine like terms. Let's proceed step by step:

Initial expression:
(3b - 2c) - (6c + 2b) - (b + c)

Distribute negative signs:
(3b - 2c) - 6c - 2b - b - c

Combine like terms:
(3b - 2b - b) + (-2c - 6c - c)

Combine b terms:
3b - 2b is b, and b - b is 0b (which is simply 0; thus, the b terms cancel out).

Combine c terms:
-2c - 6c is -8c, and -8c - c is -9c.

Therefore, after combining like terms, the result is:
0b - 9c

Since 0b is just 0, we can write the final result as:
-9c