Subtract: (3b−2c)−(6c+2b)−(b+c) .

Answer 1

To subtract (3b−2c)−(6c+2b)−(b+c), we can perform the subtraction operation inside each set of parentheses first.

Inside the first set of parentheses, we have the expression 3b−2c.
Inside the second set of parentheses, we have the expression 6c+2b.
Inside the third set of parentheses, we have the expression b+c.

Performing the subtraction inside each set of parentheses, we get:
(3b - 2c) - (6c + 2b) - (b + c)
= 3b - 2c - 6c - 2b - b - c

Now, we can combine like terms:
= (3b - 2b - b) - (2c + 6c + c)
= (0b - b) - (9c)
= -b - 9c

Thus, the simplified expression is -b - 9c.