Question

Subtract: (3b−2c)−(6c+2b)−(b+c) pls explain

Answer 1

To subtract the given expressions, we must apply the distributive property and combine like terms.

First, let's simplify each part of the expression:

3b - 2c = 3b - 2c (no change)
6c + 2b = 2b + 6c (rearranged terms)
b + c = b + c (no change)

Now, let's subtract each of these simplified expressions:

(3b - 2c) - (6c + 2b) - (b + c)

= 3b - 2c - 6c - 2b - b - c

= (3b - 2b - b) - (2c + 6c + c)

= (3 - 2 - 1)b - (2 + 6 + 1)c

= 0b - 9c

= -9c

Therefore, the simplified expression is -9c.