Subtract

Question

2(k-4)-3(2k-1)

Answer 1

To subtract the expression \(2(k-4) - 3(2k-1)\), we can first distribute the constants in front of the parentheses.

1. Distribute \(2\) in \(2(k-4)\): \[ 2(k-4) = 2k - 8 \]

2. Distribute \(-3\) in \(-3(2k-1)\): \[ -3(2k-1) = -6k + 3 \]

Now, combine the two results: \[ 2(k-4) - 3(2k-1) = (2k - 8) + (-6k + 3) \]

Next, we can combine like terms: \[ = 2k - 6k - 8 + 3 \] \[ = -4k - 5 \]

Thus, the result of the expression \(2(k-4) - 3(2k-1)\) is: \[ \boxed{-4k - 5} \]