Subtract: 2(k-4)-3(2k-1)

A. 8k-11
B. -4k-5
C. -4k-11
D. -6k-18

1 answer

To solve this problem, we distribute the numbers outside the parentheses to the terms inside the parentheses.

2(k-4) = 2k - 8
3(2k-1) = 6k - 3

Substituting these values back into the original equation, we have:

2k - 8 - 6k + 3

Next, combine like terms:

-4k - 5

Therefore, the correct answer is B. -4k - 5.