Subtract (2)/(4+sqrt6) - (2)/(4-sqrt6).

Can someone explain how to do this to me?

3 answers

Ok, so I tried to work it out myself. I think I have to rationalize the denominator for each fraction and then subtract those two answers.
That would work, but have you noticed that the denominators are conjugates of each other?
so let's do it by finding a common denominator which would be (4+√6)(4-√6) = 16 - 6 = 10
so we have

2/(4+√6) - 2/(4-√6)
= (2(4-√6) - 2(4 +√6) )/10
= (8 - 2√6 - 8 - 2√6)/10
= -4√6/10
= -2√6 /5
thank you
Similar Questions
  1. (sqrt3+5 sqrt6)(sqrt3-5 sqrt6)DRWLS-Just take the difference of the squares of the two terms, sqrt 3 and 5 sqrt6. Then you will
    1. answers icon 1 answer
  2. 1. (3-sqrt6)/(5-2sqrt6)2. (2sqrt3-sqrt6)/(5sqrt3+2sqrt6) Don't you do something with the conjugate or something like that?
    1. answers icon 0 answers
  3. This looks like a trick question(sqrt3+5 sqrt6)(sqrt3-5 sqrt6) Do I sq 3 or do I add 3 and 5 first? I think I have to do the
    1. answers icon 2 answers
  4. Find the domain of the function.f(x) = sqrt 6-x A. (-∞, 6) (6, ∞) B. (-∞, sqrt6 ) (sqrt 6 , ∞) C. (-∞, sqrt6] D.
    1. answers icon 6 answers
more similar questions