To subtract the mixed numbers \(2 \frac{3}{8}\) and \(1 \frac{2}{8}\), follow these steps:
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Convert the mixed numbers to improper fractions:
- For \(2 \frac{3}{8}\): \[ 2 \frac{3}{8} = \frac{2 \times 8 + 3}{8} = \frac{16 + 3}{8} = \frac{19}{8} \]
- For \(1 \frac{2}{8}\): \[ 1 \frac{2}{8} = \frac{1 \times 8 + 2}{8} = \frac{8 + 2}{8} = \frac{10}{8} \]
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Now subtract the two improper fractions: \[ \frac{19}{8} - \frac{10}{8} = \frac{19 - 10}{8} = \frac{9}{8} \]
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Convert the result back to a mixed number: \[ \frac{9}{8} = 1 \frac{1}{8} \]
Therefore, \(2 \frac{3}{8} - 1 \frac{2}{8} = 1 \frac{1}{8}\).
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