Subtract 12(z+4)−3(14z+1). Use fractions in final form

Answer 1

To simplify the expression \( 12(z+4) - 3(14z+1) \), we start by distributing the terms.

1. Distribute \( 12 \) in the first term: \[ 12(z+4) = 12z + 48 \]

2. Distribute \( -3 \) in the second term: \[ -3(14z+1) = -42z - 3 \]

Now, we can combine the results: \[ 12z + 48 - 42z - 3 \]

Next, combine like terms:

• Combine the \( z \) terms: \( 12z - 42z = -30z \)
• Combine the constant terms: \( 48 - 3 = 45 \)

Putting it all together gives: \[ -30z + 45 \]

We can express this in fraction form if needed. The expression can be represented as: \[ -\frac{30}{1}z + \frac{45}{1} \]

Thus, the simplified form of the expression \( 12(z+4) - 3(14z+1) \) is: \[ -30z + 45 \]