Subtract 12(z+4)−3(14z+1). Use fractions in final form.

Answer 1

To subtract 12(z+4)−3(14z+1), we first distribute the 12 and 3 to the terms inside the parentheses:

12(z+4)−3(14z+1) = 12z + 48 - 42z - 3

Next, we combine like terms:

(12z - 42z) + (48 - 3) = -30z + 45

Therefore, the final answer in fraction form is -30z + 45.