Subtract 12(z+4)−3(14z+1)

Question

. Use fractions in final form.(1 point)

Answer 1

To subtract the expression \( 12(z+4) - 3(14z+1) \), we will follow the steps of distributing and then combining like terms.

1. Distribute:

   \[ 12(z + 4) = 12z + 48 \]

   \[ -3(14z + 1) = -42z - 3 \]

2. Combine the results:

   Now we combine the two results we calculated.

   \[ 12z + 48 - 42z - 3 \]

3. Combine like terms:

   For \( z \):

   \[ 12z - 42z = -30z \]

   For the constants:

   \[ 48 - 3 = 45 \]

4. Final result:

   Putting it all together, we have:

   \[ -30z + 45 \]

Thus, the final result is:

\[ \boxed{-30z + 45} \]