Question

Subtract 12(z+4)−3(14z+1)
. Use fractions in final form.(1 point)

Answer 1

To subtract the expression \( 12(z+4) - 3(14z+1) \), we will follow the steps of distributing and then combining like terms.

1. **Distribute**:

\[
12(z + 4) = 12z + 48
\]

\[
-3(14z + 1) = -42z - 3
\]

2. **Combine the results**:

Now we combine the two results we calculated.

\[
12z + 48 - 42z - 3
\]

3. **Combine like terms**:

For \( z \):

\[
12z - 42z = -30z
\]

For the constants:

\[
48 - 3 = 45
\]

4. **Final result**:

Putting it all together, we have:

\[
-30z + 45
\]

Thus, the final result is:

\[
\boxed{-30z + 45}
\]