Subtract 12(z+4)−3(14z+1). Use fractions in final form.(1 point)

Answer 1

To subtract 12(z+4)−3(14z+1), we will distribute the 12 and the 3 to both terms inside the parentheses:

12(z+4) = 12z + 48
3(14z+1) = 42z + 3

Now we can subtract the two expressions:

12z + 48 - (42z + 3)

To subtract, we can combine like terms:

12z - 42z + 48 - 3

-30z + 45

So the final answer, using fractions, is -30z + 45.