Subtract 12(z+4)−3(14z+1) . Use fractions in final form.(1 point)

Answer 1

To subtract 12(z+4)−3(14z+1), we can apply the distributive property to each term inside the parentheses:

12(z+4) = 12z + 12(4) = 12z + 48
3(14z+1) = 3(14z) + 3(1) = 42z + 3

Now we can subtract the two expressions:

(12z + 48) - (42z + 3) = 12z - 42z + 48 - 3 = -30z + 45

So, 12(z+4)−3(14z+1) simplifies to -30z + 45.