Subtract 12(z+4)−3(14z+1) . Use fractions in final form.(1 point)

Answer 1

To solve this expression, we distribute the numbers outside the parentheses to the numbers inside.

12(z+4) becomes 12z + 48.
-3(14z + 1) becomes -42z - 3.

Now we can combine like terms by subtracting the second expression from the first:

(12z + 48) - (-42z - 3)
= 12z + 48 + 42z + 3
= 54z + 51

So, the final answer is 54z + 51.