Subtract 12(z+4)−3(14z+1)

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. Use fractions in final form.(1 point)

1 answer

To simplify the expression \( 12(z + 4) - 3(14z + 1) \), let's follow the steps carefully:

  1. Distribute the terms inside the parentheses: \[ 12(z + 4) = 12z + 48 \] \[ -3(14z + 1) = -42z - 3 \]

  2. Combine these results: \[ 12z + 48 - 42z - 3 \]

  3. Combine like terms:

    • For the \(z\) terms: \[ 12z - 42z = -30z \]
    • For the constant terms: \[ 48 - 3 = 45 \]
  4. Putting it all together: \[ -30z + 45 \]

Thus, the simplified expression is: \[ -30z + 45 \]

If you need to express it in fractional form, you could rewrite it as: \[ -30z + \frac{45}{1} \] But in this case, keeping it as \( -30z + 45 \) is acceptable and clear.

So, the final answer is: \[ -30z + 45 \]