Subtract 12(z+4)−3(14z+1)

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2
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. Use fractions in final form.(1 point)....................

1 answer

Let's simplify the expression step by step:

Given:

\[ 12(z + 4) - 3(14z + 1) \]

  1. Distribute the 12 and -3:

\[ 12(z) + 12(4) - 3(14z) - 3(1) \]

This simplifies to:

\[ 12z + 48 - 42z - 3 \]

  1. Combine like terms:

Combine \(12z\) and \(-42z\):

\[ 12z - 42z = -30z \]

Combine \(48\) and \(-3\):

\[ 48 - 3 = 45 \]

So the expression simplifies to:

\[ -30z + 45 \]

  1. To express this in fractional form, we can factor out the common factor, if necessary:

\[ -30z + 45 = -15(2z - 3) \]

Thus, the final answer as a fraction is:

\[ -15(2z - 3) \]

Alternatively, you can express this in terms of fractions if needed:

\[ -30z + 45 = \frac{-30z + 45}{1} \]

So, the simplified expression is:

\[ -30z + 45 \] or \(-15(2z - 3)\).