Put y = - 2 x + 2 in L2
3 x + 2 y = 5
3 x + 2 ∙ ( - 2 x + 2 ) = 5
3 x - 4 x + 4 = 5
- x + 4 = 5
Subtract 4 to both sides
- x = 1
Multiply both sides by - 1
x = - 1
Put this value in equation:
3 x + 2 y = 5
3 ∙ ( - 1 ) + 2 y = 5
- 3 + 2 y = 5
Add 3 to both sides
2 y = 8
y = 8 / 2 = 4
Substitution Method
L1: y= -2x+2
L2: 3x+2y=5
1 answer