From the 2nd: m+2n=3
m = 3 - 2n
sub into the first:
4m - 3n = 0
4(3 - 2n) - 3n = 0
now you have only n's,
carry on.
substitution method 4m-3n=0 and m+2n=3
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Will they not collect like terms
Dullards
I don't understand
I don't understand
Esther
4m-3n=0