no.Ag^+ + e ==> Ag is -0.80
Cu^2+ + 2e = Cu is +0.34
Add them. Your sign is wrong.
Study the two half reactions of an electrochemical cell.
Ag(s) → Ag^+(aq) + e^–
E^0 = 0.80 V
Cu(s) → Cu^2+(aq) + 2e^–
E^0 = 0.34 V
Which option correctly gives the standard cell potential of
Ag^+(aq) + Cu (s) → 2Ag(s) + Cu^2+(aq) reaction?
The answer I got is 0.46 is this correct?
2 answers
Oh, I see. Thank you, Dr. Bob.