i.
Let X be the number of students from rural family out of 10 students randomly selected.
To find the probability that less than two students come from rural family, we need to find P(X < 2).
P(X < 2) = P(X = 0) + P(X = 1)
P(X = 0) = (0.55)^10 = 0.00193165
P(X = 1) = 10C1 * (0.45)^1 * (0.55)^9 = 0.03054506
P(X < 2) = 0.00193165 + 0.03054506 = 0.03247671
Therefore, the probability that less than two students come from rural family if ten students are randomly selected is 0.0325.
ii.
Let Y be the number of students from rural family out of 7 students randomly selected.
To find the probability that greater than at least one students come from rural family, we need to find 1 minus the probability that no student comes from rural family.
P(Y > 0) = 1 - P(Y = 0)
P(Y = 0) = (0.55)^7 = 0.03445339
P(Y > 0) = 1 - 0.03445339 = 0.96554661
Therefore, the probability that greater than at least one students come from rural family if seven students are randomly selected is 0.9655.
Study shows that 45% of students in SMK Cemerlang come from rural family.
i. Find the probability that less than two students come from rural family if ten students are randomly selected.
ii. Find the probability that greater than at least one students come from rural family if seven students are randomly.
Calculate the right answer for both questions
1 answer