To simplify the expression \((2^2 \cdot 2^{-6})^{-3} \cdot (2)^0\), we'll go through the steps carefully.
Step 1: Simplify the Inner Expression
First, we simplify the expression inside the parentheses: \[ 2^2 \cdot 2^{-6} \] Using the rule of exponents \(a^m \cdot a^n = a^{m+n}\), we can combine the exponents: \[ 2^{2 + (-6)} = 2^{-4} \]
Step 2: Apply the Outer Exponent
Next, we apply the exponent \(-3\) to the simplified expression: \[ (2^{-4})^{-3} \] Using the power of a power rule, \( (a^m)^n = a^{m \cdot n} \): \[ 2^{-4 \cdot -3} = 2^{12} \]
Step 3: Include the \((2)^0\) term
Now, we consider the \((2)^0\) term: \[ (2^{12}) \cdot (2^0) \] Using the same exponent rule \(a^m \cdot a^n = a^{m+n}\), we combine these: \[ 2^{12 + 0} = 2^{12} \]
Conclusion
So the entire expression simplifies to: \[ 2^{12} \]
Answer
The correct answer to the expression is: \[ 2^{12} \]
Evaluating Errors:
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John's Error: John mistakenly thinks the entire expression evaluates to 1 based on \((2)^0\) being 1. However, he didn't account for the rest of the expression that doesn't evaluate to 0.
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Carol's Error: Carol incorrectly interpreted the operations. While she correctly combined the exponents, she misapplied the rescaling of the result, suggesting \(4^{12}\) rather than recognizing the original base \(2\).
Final Result
To present the final answer, if desired in numerical form: \[ 2^{12} = 4096 \]